Mary Moreland · 1917
Mary Moreland (1917) is a Drama film directed by Frank Powell, starring Marjorie Rambeau, Robert Elliott, Jean La Motte.
Drama
Overview
Wealthy Wall Street broker Thomas Maughm finally decides to divorce his spendthrift and reckless wife, and dictates a letter to that affect to his stenographer, Mary Moreland. While dictating the letter, he realizes that he is actually in love with Mary; when he tells her this, she confesses that she loves him, also, The pair make plans to meet in Boston later that night, but before Mary leaves, Maughm's wife confronts her and tells Mary that she still loves her husband. Ashamed, Mary convinces Maughm to go back to his wife. Complications ensue.
Cast
Marjorie Rambeau, Robert Elliott, Jean La Motte, Augusta Burmeister, Fraser Tarbutt, Edna Holland, Frank A. Ford
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What is "Mary Moreland" about?
Wealthy Wall Street broker Thomas Maughm finally decides to divorce his spendthrift and reckless wife, and dictates a letter to that affect to his stenographer, Mary Moreland. While dictating the letter, he realizes that he is actually in love with Mary; when he tells her this, she confesses that she loves him, also, The pair make plans to meet in Boston later that night, but before Mary leaves, Maughm's wife confronts her and tells Mary that she still loves her husband. Ashamed, Mary convinces Maughm to go back to his wife. Complications ensue.
When was "Mary Moreland" released?
Mary Moreland was released in 1917.
Who stars in "Mary Moreland"?
The cast includes Marjorie Rambeau, Robert Elliott, Jean La Motte, Augusta Burmeister.
